(-5x-1*2x^2)=(2x^2)

Solution for (-5x-1*2x^2)=(2x^2) equation:

(-5x-1*2x^2)=(2x^2)

We move all terms to the left:

(-5x-1*2x^2)-((2x^2))=0

determiningTheFunctionDomain
(-5x-1*2x^2)-2x^2=0

We add all the numbers together, and all the variables

-2x^2+(-5x-1*2x^2)=0

We get rid of parentheses

-2x^2-5x-1*2x^2=0

Wy multiply elements

-2x^2-2x^2-5x=0

We add all the numbers together, and all the variables

-4x^2-5x=0

a = -4; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-4)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-4}=\frac{10}{-8}
=-1+1/4
$